x^2+4x-10x+40=0

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Solution for x^2+4x-10x+40=0 equation:


Simplifying
x2 + 4x + -10x + 40 = 0

Reorder the terms:
40 + 4x + -10x + x2 = 0

Combine like terms: 4x + -10x = -6x
40 + -6x + x2 = 0

Solving
40 + -6x + x2 = 0

Solving for variable 'x'.

Begin completing the square.

Move the constant term to the right:

Add '-40' to each side of the equation.
40 + -6x + -40 + x2 = 0 + -40

Reorder the terms:
40 + -40 + -6x + x2 = 0 + -40

Combine like terms: 40 + -40 = 0
0 + -6x + x2 = 0 + -40
-6x + x2 = 0 + -40

Combine like terms: 0 + -40 = -40
-6x + x2 = -40

The x term is -6x.  Take half its coefficient (-3).
Square it (9) and add it to both sides.

Add '9' to each side of the equation.
-6x + 9 + x2 = -40 + 9

Reorder the terms:
9 + -6x + x2 = -40 + 9

Combine like terms: -40 + 9 = -31
9 + -6x + x2 = -31

Factor a perfect square on the left side:
(x + -3)(x + -3) = -31

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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